e) \( P=A\left(1+\frac{r n}{100}\right) \) kan gebruik word om die waarde van ' \( n \) belegging, \( P \), te bereken indien 'n oorspronklike belegging, \( A \), teen \( r \% \) enkelvoudige rente belê word vir \( n \) jare. (1) Maak \( r \) die onderwerp van die formule. (2) Bereken \( r \) indien \( A=\mathrm{R} 1000, P=\mathrm{R} 3000 \) en \( n=5 \) jare. LINEERE ONGELYKHEDE
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Om \( r \) die onderwerp van die formule te maak, begin ons met die oorspronklike vergelyking: \[ P = A\left(1 + \frac{r n}{100}\right) \] Eerstens, deel met \( A \): \[ \frac{P}{A} = 1 + \frac{r n}{100} \] Nou trek ons 1 af: \[ \frac{P}{A} - 1 = \frac{r n}{100} \] Vermenigvuldig met 100: \[ 100\left(\frac{P}{A} - 1\right) = r n \] Laastens, deel deur \( n \): \[ r = \frac{100}{n}\left(\frac{P}{A} - 1\right) \] Nou om \( r \) te bereken: Plug die waardes in die formule in, waar \( A = R1000 \), \( P = R3000 \), en \( n = 5 \). \[ r = \frac{100}{5}\left(\frac{3000}{1000} - 1\right) \] \[ r = 20 \left(3 - 1\right) = 20 \times 2 = 40 \] So, \( r = 40\% \) is die jaarlikse rente.