Find the common factors of the given terms in each 1) \( 12 x^{2} y, 18 x y^{2} \)
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Bonus Knowledge
To find the common factors, let's break each term down into its prime factors and variable components. For \( 12 x^{2} y \): \( 12 = 2^2 \times 3 \), and the variables are \( x^2 \) and \( y \). So, \( 12 x^{2} y = 2^2 \times 3 \times x^2 \times y \). For \( 18 x y^{2} \): \( 18 = 2 \times 3^2 \), and the variables are \( x \) and \( y^2 \). So, \( 18 x y^{2} = 2 \times 3^2 \times x \times y^2 \). Now, identify the common prime factors: - For \( 2 \): The minimum power is \( 2^1 \) (from \( 18 \)). - For \( 3 \): The minimum power is \( 3^1 \) (from \( 12 \)). - For variables \( x \): The minimum power is \( x^1 \) (from \( 18 \)). - For variables \( y \): The minimum power is \( y^1 \) (from \( 12 \)). Now, combining these common factors, we get: Common factors = \( 2^1 \times 3^1 \times x^1 \times y^1 = 6xy \). So, the common factors of \( 12 x^{2} y \) and \( 18 x y^{2} \) are \( 6xy \).