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Name: Fractions with Unlike ,enominators * Show all work ind the value of each expression in lowest terms. On the bock or another paper 1) \( \frac{7}{8}+\frac{2}{8}= \) \( \qquad \) 2) \( \frac{4}{6}+\frac{6}{11}= \) \( \qquad \) 3) \( \frac{8}{9}+\frac{3}{5}= \) \( \qquad \) 5) \( \frac{2}{4}+\frac{3}{6}= \) \( \qquad \) \( 7 \frac{4}{8}+\frac{5}{10}= \) \( \qquad \) 8) \( \frac{2}{4}-\frac{1}{5}= \) \( \qquad \) 10) \( \frac{2}{3}-\frac{1}{2}= \) \( \qquad \) 9) \( \frac{3}{8}-\frac{2}{7}= \) \( \qquad \) 11) \( \frac{2}{6}-\frac{2}{0}= \) 12) \( \frac{10}{11}-\frac{5}{10}= \) \( \qquad \)

Ask by Conner Horton. in the United States
Feb 24,2025

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1) \( \frac{9}{8} \) 2) \( \frac{40}{33} \) 3) \( \frac{67}{45} \) 4) \( 1 \) 5) \( 1 \) 6) \( \frac{3}{10} \) 7) \( \frac{1}{6} \) 8) \( \frac{5}{56} \) 9) Undefined (division by zero) 10) \( \frac{9}{22} \)

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To tackle fractions with unlike denominators, we need to find a common denominator for the fractions we’re adding or subtracting. For example, adding \( \frac{4}{6} + \frac{6}{11} \) requires us to find the least common multiple of 6 and 11, which is 66. Next, we rewrite each fraction: \( \frac{4}{6} = \frac{44}{66} \) and \( \frac{6}{11} = \frac{36}{66} \), so we add \( 44 + 36 = 80 \) over the common denominator 66. This results in \( \frac{80}{66} = \frac{40}{33} \) when reduced! When performing operations with fractions, it's easy to make mistakes such as manipulating the wrong denominators or forgetting to simplify. A common pitfall is assuming that you can directly add or subtract the numerators while keeping the denominators separate without finding a common one first. Always double-check your denominators and aim for simplified forms to avoid computation headaches later on!

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