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\( f ( x ) = x ^ { 2 } + 4 x + 1 , \quad c = 1 \)

Ask by Campbell Mann. in Italy
Nov 22,2024

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Tutor-Verified Answer

Answer

\( f(1) = 6 \)

Solution

Per la funzione \( f(x) = x^2 + 4x + 1 \) e il valore \( c = 1 \), possiamo calcolare il valore della funzione in \( c \): \[ f(1) = 1^2 + 4 \cdot 1 + 1 \] Calcoliamo passo dopo passo: \[ f(1) = 1 + 4 + 1 = 6 \] Quindi, \( f(1) = 6 \). Se hai bisogno di ulteriori informazioni o di un'analisi della funzione, fammelo sapere!

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Bonus Knowledge

Did you know that the function \( f(x) = x^2 + 4x + 1 \) is a quadratic function, and its graph is a parabola? The vertex of this parabola can be found using the formula \( x = -\frac{b}{2a} \), where \( a = 1 \) and \( b = 4 \). By calculating this, we find the vertex lies at \( x = -2 \), making it a great place to understand the function's minimum value! In real-world applications, quadratics like this can model various situations such as projectile motion or optimizing area. For instance, if you were designing a garden, you could use a quadratic model to determine the maximum area you can achieve with a given perimeter. It's a practical tool in fields like architecture and environmental design!

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