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Factor completely. \( 5 g^{2}+24 g-5 \) \( \square \) Submit

Ask by Spencer Nunez. in the United States
Mar 12,2025

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Tutor-Verified Answer

Answer

\(5g^{2}+24g-5\) factors to \((g+5)(5g-1)\).

Solution

Factor the expression \( 5g^2+24g-5 \). Factor the expression by following steps: - step0: Factor: \(5g^{2}+24g-5\) - step1: Rewrite the expression: \(5g^{2}+\left(-1+25\right)g-5\) - step2: Calculate: \(5g^{2}-g+25g-5\) - step3: Rewrite the expression: \(g\times 5g-g+5\times 5g-5\) - step4: Factor the expression: \(g\left(5g-1\right)+5\left(5g-1\right)\) - step5: Factor the expression: \(\left(g+5\right)\left(5g-1\right)\) The factored form of the expression \(5g^{2}+24g-5\) is \((g+5)(5g-1)\).

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Mind Expander

To factor the quadratic expression \( 5g^{2} + 24g - 5 \), we look for two numbers that multiply to \( 5 \times -5 = -25 \) and add to \( 24 \). The numbers \( 25 \) and \( -1 \) fit the bill perfectly! We rewrite the expression as: \( 5g^{2} + 25g - g - 5 \). Next, we can group and factor by grouping: \( (5g^{2} + 25g) + (-g - 5) \) which gives us: \( 5g(g + 5) - 1(g + 5) \). Now, we factor out \( (g + 5) \): \( (g + 5)(5g - 1) \). So, the completely factored form of \( 5g^{2} + 24g - 5 \) is \( (g + 5)(5g - 1) \). Now you can dazzle your friends with your factoring prowess! 🌟

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