Find one value of \( x \) that is a solution to the equation: \( \begin{array}{l}(2 x+3)^{2}-6 x-9=0 \\ x=\end{array} \)
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Bonus Knowledge
To solve the equation \((2x+3)^{2}-6x-9=0\), we first expand and simplify the left side. 1. Expand the squared term: \((2x+3)^{2} = 4x^{2} + 12x + 9\). 2. Substitute it back into the equation: \(4x^{2} + 12x + 9 - 6x - 9 = 0\). 3. Simplify the equation: \(4x^{2} + (12x - 6x) + (9 - 9) = 0\), \(4x^{2} + 6x = 0\). 4. Factor out the common term: \(2x(2x + 3) = 0\). 5. Set each factor to zero: \(2x = 0 \implies x = 0\), \(2x + 3 = 0 \implies 2x = -3 \implies x = -\frac{3}{2}\). Thus, one value of \( x \) that is a solution to the equation is \( x = 0 \).