Question
Question 5 Evaluate the expression: \( \log _{1 / 2} 64 \).
Ask by Frank Weaver. in the United States
Mar 19,2025
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Answer
\( \log_{1/2} 64 = -6 \)
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To evaluate \( \log_{1/2} 64 \), we're essentially asking: "To what power must I raise \( 1/2 \) to get \( 64 \)?" Since \( 64 \) can be expressed as \( 2^6 \), we can rewrite \( 1/2 \) as \( 2^{-1} \). Therefore, the expression becomes \( \log_{2^{-1}} 2^6 \). Using the change of base formula, we have: \[ \log_{2^{-1}} 2^6 = \frac{\log_2 2^6}{\log_2 2^{-1}} = \frac{6}{-1} = -6. \] Thus, \( \log_{1/2} 64 = -6 \).