Solve for \( x \) \[ x^{2}-8 x+16=0 \] If there is more than one solution, separate them with commas. If there is no solution, click on "No solution." \( x=\square \)

1. Recognize that the quadratic equation is \[ x^2 - 8x + 16 = 0. \] 2. Observe that the quadratic can be written as a perfect square. Notice that \[ (x - 4)^2 = x^2 - 8x + 16. \] 3. Rewrite the equation using the perfect square: \[ (x - 4)^2 = 0. \] 4. Set the expression inside the square equal to zero: \[ x - 4 = 0. \] 5. Solve for \( x \): \[ x = 4. \] 6. Since the equation has a double solution, the only solution is \[ x = 4. \]