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Solve for \( y \) \[ 9(y+k)=C \] \( y=\square \)

Ask by Flynn Mullins. in the United States
Feb 21,2025

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\( y = \frac{C - 9k}{9} \)

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The Deep Dive

To solve for \( y \), we start by isolating \( y \) in the equation \( 9(y + k) = C \). Begin by dividing both sides by 9: \[ y + k = \frac{C}{9} \] Next, subtract \( k \) from both sides to solve for \( y \): \[ y = \frac{C}{9} - k \] So, the final expression for \( y \) is: \[ y = \frac{C}{9} - k \]

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