4. solve \( 3 c+b c=b \) for \( b \)

To solve for \( b \) in the equation \( 3c + bc = b \), we can first rearrange the equation. Start by moving all terms involving \( b \) to one side: \[ bc - b = -3c \] Next, we can factor out \( b \): \[ b(c - 1) = -3c \] Now, divide both sides by \( c - 1 \) (assuming \( c \neq 1 \)) to isolate \( b \): \[ b = \frac{-3c}{c - 1} \] And there you have the solution for \( b \) in terms of \( c \)!