Question
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Perform the operation indicated. Simplify. \( \frac{x+2 y}{24 x^{2}} \cdot \frac{3 x}{x^{2}+x y-2 y^{2}} \)

Ask by Blake Valdez. in the United States
Jan 31,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

\[ \frac{1}{8x(x - y)} \]

Solution

To simplify the expression: \[ \frac{x + 2y}{24x^2} \cdot \frac{3x}{x^2 + xy - 2y^2} \] **Step 1: Factor the Denominator** First, factor the quadratic expression in the denominator: \[ x^2 + xy - 2y^2 \] This factors as: \[ (x + 2y)(x - y) \] **Step 2: Rewrite the Expression** Substitute the factored form into the original expression: \[ \frac{x + 2y}{24x^2} \cdot \frac{3x}{(x + 2y)(x - y)} \] **Step 3: Cancel Common Factors** Notice that \((x + 2y)\) appears in both the numerator and the denominator, so they cancel out: \[ \frac{3x}{24x^2(x - y)} \] **Step 4: Simplify the Coefficients and Variables** Simplify the coefficients and the variables: \[ \frac{3x}{24x^2(x - y)} = \frac{3}{24x(x - y)} = \frac{1}{8x(x - y)} \] **Final Answer:** \[ \boxed{\dfrac{1}{8\,x\,\left(x - y\,\right)}} \]

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Let's simplify the expression step-by-step. We have: \[ \frac{x+2y}{24x^{2}} \cdot \frac{3x}{x^{2}+xy-2y^{2}} \] First, we can multiply the fractions: \[ = \frac{(x+2y) \cdot (3x)}{24x^{2} \cdot (x^{2}+xy-2y^{2})} \] Now, the numerator simplifies to: \[ 3x(x + 2y) = 3x^2 + 6xy \] Next, we will leave the denominator as is for now: \[ = \frac{3x^2 + 6xy}{24x^{2}(x^{2}+xy-2y^{2})} \] To simplify further, we can factor out the numerator: \[ = \frac{3x(x + 2y)}{24x^{2}(x^{2}+xy-2y^{2})} \] Now we can reduce the fraction by canceling common factors. Notice that \(3\) and \(24\) can simplify: \[ = \frac{x(x + 2y)}{8x^{2}(x^{2}+xy-2y^{2})} \] Now cancelling an \(x\) from the numerator and denominator (assuming \(x \neq 0\)) gives us: \[ = \frac{x + 2y}{8x(x^{2}+xy-2y^{2})} \] Thus, the simplified form of the given expression is: \[ \frac{x + 2y}{8x(x^{2}+xy-2y^{2})} \]

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