\( \triangle S C A \) can be mapped onto \( \triangle M B G \) by a rotation. \( \mathrm{m} \angle A=144^{\circ} \) and \( \mathrm{m} \angle S=28^{\circ} \), find \( \mathrm{m} \angle B \). Answer Attempt out o o 55 \( \mathrm{~m} \angle B \quad \) be determined.
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Beyond the Answer
To find \( \mathrm{m} \angle B \) in triangle \( \triangle M B G \), we first need to find \( \mathrm{m} \angle C \) in triangle \( \triangle S C A \). Since the sum of the angles in any triangle is \( 180^{\circ} \), we can calculate: \[ \mathrm{m} \angle C = 180^{\circ} - \mathrm{m} \angle A - \mathrm{m} \angle S \] \[ \mathrm{m} \angle C = 180^{\circ} - 144^{\circ} - 28^{\circ} \] \[ \mathrm{m} \angle C = 180^{\circ} - 172^{\circ} = 8^{\circ} \] Now, since \( \triangle S C A \) can be mapped to \( \triangle M B G \) by a rotation, the angles correspond to each other. Therefore, \( \mathrm{m} \angle B = \mathrm{m} \angle C = 8^{\circ} \). Thus, \( \mathrm{m} \angle B = 8^{\circ} \).