Multiply: \( \begin{array}{c}\left(\frac{1}{6} m^{9} n^{4}\right)\left(\frac{7}{5} m^{2} n^{3}\right)= \\ \text { A } \frac{7}{30} m^{11} n^{4} \\ \text { B } \frac{7}{30} m^{11} n^{7} \\ \text { C } \frac{7}{30} n^{11} m^{7} \\ \text { D } \frac{7}{30} m^{9} n^{7}\end{array} \)

We start with the expression: \[ \left(\frac{1}{6} m^{9} n^{4}\right)\left(\frac{7}{5} m^{2} n^{3}\right) \] 1. Multiply the coefficients: \[ \frac{1}{6} \times \frac{7}{5} = \frac{7}{30} \] 2. Apply the laws of exponents for \( m \): \[ m^{9} \times m^{2} = m^{9+2} = m^{11} \] 3. Apply the laws of exponents for \( n \): \[ n^{4} \times n^{3} = n^{4+3} = n^{7} \] Combining these results, we have: \[ \frac{7}{30} m^{11} n^{7} \] Thus, the correct answer is: B \(\frac{7}{30} m^{11} n^{7}\)