Find \( f+g, f-g \), \( f g \), and \( \frac{f}{g} \). Determine the domain for each function. \( f(x)=x+1, g(x)=5 x^{2} \) \( (f+g)(x)=5 x^{2}+x+1 \) (Simplify your answer.) What is the domain of \( f+g \) ? A. The domain of \( f+g \) is B. The domain of \( f+g \) is \( \{ \) (Type your answer in interval notation.) (Use a comma to separate answers as needed.) C. The domain of \( f+g \) is \( \varnothing \).
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To find \( f-g \), \( fg \), and \( \frac{f}{g} \): 1. **For \( f-g \)**: \[ (f-g)(x) = f(x) - g(x) = (x + 1) - (5x^2) = -5x^2 + x + 1. \] 2. **For \( fg \)**: \[ (fg)(x) = f(x) \cdot g(x) = (x + 1)(5x^2) = 5x^3 + 5x^2. \] 3. **For \( \frac{f}{g} \)**: \[ \left(\frac{f}{g}\right)(x) = \frac{f(x)}{g(x)} = \frac{x + 1}{5x^2}. \] This is defined for all \( x \) except where \( g(x) = 0 \). Since \( g(x) = 5x^2 \), it's zero at \( x=0 \). Now, let's determine the domains: A. The domain of \( f+g \) is all real numbers since both \( f(x) \) and \( g(x) \) have no restrictions on their domains. B. The domain of \( f+g \) is \( (-\infty, \infty) \). C. The domain of \( f-g \) is also \( (-\infty, \infty) \), since it's a polynomial. For \( fg \): The domain of \( fg \) is \( (-\infty, \infty) \) as well. For \( \frac{f}{g} \): Since \( \frac{f}{g}(x) \) is undefined at \( x=0 \), the domain is all real numbers except 0. The final domain for \( \frac{f}{g} \) is \( (-\infty, 0) \cup (0, \infty) \).