\( \begin{array}{l}\text { QUESTION } \\ \text { Solve for } x\end{array} 4 x^{2}-4 x+1 \leq 0 \)

Solve the equation \( 4x^2-4x+1 \leq 0 \). Solve the inequality by following steps: - step0: Solve the inequality by testing the values in the interval: \(4x^{2}-4x+1\leq 0\) - step1: Rewrite the expression: \(4x^{2}-4x+1=0\) - step2: Factor the expression: \(\left(2x-1\right)^{2}=0\) - step3: Simplify the expression: \(2x-1=0\) - step4: Move the constant to the right side: \(2x=0+1\) - step5: Remove 0: \(2x=1\) - step6: Divide both sides: \(\frac{2x}{2}=\frac{1}{2}\) - step7: Divide the numbers: \(x=\frac{1}{2}\) - step8: Determine the test intervals: \(\begin{align}&x<\frac{1}{2}\\&x>\frac{1}{2}\end{align}\) - step9: Choose a value: \(\begin{align}&x_{1}=-1\\&x_{2}=2\end{align}\) - step10: Test the chosen value: \(\begin{align}&x<\frac{1}{2}\textrm{ }\textrm{is not a solution}\\&x>\frac{1}{2}\textrm{ }\textrm{is not a solution}\end{align}\) - step11: The final solution is \(x=\frac{1}{2}:\) \(x=\frac{1}{2}\) The solution to the inequality \(4x^{2}-4x+1 \leq 0\) is \(x \leq 0.5\).