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Simplify the following complex rational expression. \[ \frac{-\frac{6}{x+4}+\frac{2}{x-5}}{-\frac{3}{x+4}} \]

Ask by Bush Allan. in the United States
Jan 13,2025

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The simplified form of the expression is \(\frac{4x - 38}{3(x - 5)}\).

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To simplify the complex rational expression \[ \frac{-\frac{6}{x+4}+\frac{2}{x-5}}{-\frac{3}{x+4}}, \] we start by addressing the numerator and the denominator separately. **Step 1: Simplify the numerator.** The numerator is \[ -\frac{6}{x+4} + \frac{2}{x-5}. \] To combine these fractions, we need a common denominator, which is \((x + 4)(x - 5)\): \[ -\frac{6(x - 5)}{(x + 4)(x - 5)} + \frac{2(x + 4)}{(x + 4)(x - 5)}. \] Expanding each fraction: - The first term becomes: \[ -\frac{6x - 30}{(x + 4)(x - 5)} = \frac{-6x + 30}{(x + 4)(x - 5)}. \] - The second term becomes: \[ \frac{2x + 8}{(x + 4)(x - 5)}. \] Combining the two terms in the numerator: \[ \frac{-6x + 30 + 2x + 8}{(x + 4)(x - 5)} = \frac{-4x + 38}{(x + 4)(x - 5)}. \] Thus, the numerator simplifies to: \[ \frac{-4x + 38}{(x + 4)(x - 5)}. \] **Step 2: Simplify the denominator.** The denominator is \[ -\frac{3}{x + 4}. \] Now we can rewrite the complex fraction: \[ \frac{\frac{-4x + 38}{(x + 4)(x - 5)}}{-\frac{3}{x + 4}}. \] **Step 3: Simplify the complex fraction.** When dividing fractions, we multiply by the reciprocal: \[ \frac{-4x + 38}{(x + 4)(x - 5)} \cdot \frac{x + 4}{-3}. \] The \( (x + 4) \) in the numerator and denominator cancels out: \[ \frac{-4x + 38}{-3(x - 5)}. \] The negative signs can also be canceled, leading us to: \[ \frac{4x - 38}{3(x - 5)}. \] **Step 4: Factor out a common factor in the numerator.** Factoring out a 2 from the numerator gives: \[ \frac{2(2x - 19)}{3(x - 5)}. \] Thus, the simplified result for the complex rational expression is \[ \frac{2(2x - 19)}{3(x - 5)}. \]

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