Question
upstudy study bank question image url

a. म.स. (HCF) निकालन्नुहोस। \( x^{2}+2 x y+y^{2}-z^{2} x y^{2}+2 y z+z^{2}-x^{2}(3) \) b. सरल गर्नुहोस: (1) \( \left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(\frac{a^{z+x}}{a^{y}}\right)^{z-x} \)

Ask by Delgado Dawson. in Nepal
Mar 09,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

a. Cannot determine the HCF with the given expression. b. The expression simplifies to 1.

Solution

Simplify the expression by following steps: - step0: Solution: \(\left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(\frac{a^{z+x}}{a^{y}}\right)^{z-x}\) - step1: Multiply by \(a^{-n}:\) \(\left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\) - step2: Multiply by \(a^{-n}:\) \(\left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\) - step3: Multiply by \(a^{-n}:\) \(\left(a^{x+y}\times a^{-z}\right)^{x-y}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\) - step4: Multiply: \(\left(a^{x+y-z}\right)^{x-y}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\) - step5: Transform the expression: \(a^{\left(x+y-z\right)\left(x-y\right)}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\) - step6: Multiply: \(a^{\left(x+y-z\right)\left(x-y\right)}\left(a^{y+z-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\) - step7: Transform the expression: \(a^{\left(x+y-z\right)\left(x-y\right)}\times a^{\left(y+z-x\right)\left(y-z\right)}\left(a^{z+x}\times a^{-y}\right)^{z-x}\) - step8: Multiply: \(a^{\left(x+y-z\right)\left(x-y\right)}\times a^{\left(y+z-x\right)\left(y-z\right)}\left(a^{z+x-y}\right)^{z-x}\) - step9: Transform the expression: \(a^{\left(x+y-z\right)\left(x-y\right)}\times a^{\left(y+z-x\right)\left(y-z\right)}\times a^{\left(z+x-y\right)\left(z-x\right)}\) - step10: Multiply the terms: \(a^{\left(x+y-z\right)\left(x-y\right)+\left(y+z-x\right)\left(y-z\right)+\left(z+x-y\right)\left(z-x\right)}\) - step11: Add the terms: \(a^{0}\) - step12: Evaluate the power: \(1\) Let's solve the problems step by step. ### a. Finding the HCF (Highest Common Factor) The expression given is: \[ x^{2}+2xy+y^{2}-z^{2}xy^{2}+2y z+z^{2}-x^{2}(3) \] However, it seems that the expression is not in a standard form for finding the HCF. The HCF is typically calculated for a set of numbers or polynomials. Since the expression is complex and does not represent a clear set of terms, I cannot directly compute the HCF from it. If you have specific terms or polynomials you want to find the HCF for, please provide them. ### b. Simplifying the Expression The expression to simplify is: \[ \left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(\frac{a^{z+x}}{a^{y}}\right)^{z-x} \] The result of this simplification is: \[ 1 \] This means that the entire expression simplifies to 1. If you have any further questions or need additional assistance, feel free to ask!

Answered by UpStudy AI and reviewed by a Professional Tutor

error msg
Explain
Simplify this solution

Beyond the Answer

पहिलो भागको म.स. निकाल्नको लागि, हामी समिकरणलाई पुनर्व्यवस्थित गरौं र सामान्य कारकहरूको समूह बनाएर आंतरक्रियालाई ध्यानमा राख्नुपर्छ। त्यसपछि, हरिऔंको थालनीमा \(xy^2\) र शेष तत्वहरूको पुनरावलोकन गर्दा, सामान्य तत्त्वहरू जस्तै \(x\), \(y\), र \(z\) को जोडले म.स. भन्न सकिन्छ। दोस्रो भागलाई सरल बनाउनको लागि, प्रत्येक अंशको आधारलाई समेटेर एकै ठाउँमा ल्याइँदा, हामी गणितीय गुणनको विशेषता प्रयोग गर्न सक्छौं। यद्यपि, अंशहरूलाई पुन: व्यवस्थित गरिसकेपछि, आधारको समानता र घटावको नियम प्रयोग गरेर हामीले विश्वसनीय उत्तर सजिलै प्राप्त गर्न सक्छौं।

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy