Question
a. म.स. (HCF) निकालन्नुहोस। \( x^{2}+2 x y+y^{2}-z^{2} x y^{2}+2 y z+z^{2}-x^{2}(3) \) b. सरल गर्नुहोस: (1) \( \left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(\frac{a^{z+x}}{a^{y}}\right)^{z-x} \)
Ask by Delgado Dawson. in Nepal
Mar 09,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
a. Cannot determine the HCF with the given expression.
b. The expression simplifies to 1.
Solution
Simplify the expression by following steps:
- step0: Solution:
\(\left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(\frac{a^{z+x}}{a^{y}}\right)^{z-x}\)
- step1: Multiply by \(a^{-n}:\)
\(\left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\)
- step2: Multiply by \(a^{-n}:\)
\(\left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\)
- step3: Multiply by \(a^{-n}:\)
\(\left(a^{x+y}\times a^{-z}\right)^{x-y}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\)
- step4: Multiply:
\(\left(a^{x+y-z}\right)^{x-y}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\)
- step5: Transform the expression:
\(a^{\left(x+y-z\right)\left(x-y\right)}\left(a^{y+z}\times a^{-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\)
- step6: Multiply:
\(a^{\left(x+y-z\right)\left(x-y\right)}\left(a^{y+z-x}\right)^{y-z}\left(a^{z+x}\times a^{-y}\right)^{z-x}\)
- step7: Transform the expression:
\(a^{\left(x+y-z\right)\left(x-y\right)}\times a^{\left(y+z-x\right)\left(y-z\right)}\left(a^{z+x}\times a^{-y}\right)^{z-x}\)
- step8: Multiply:
\(a^{\left(x+y-z\right)\left(x-y\right)}\times a^{\left(y+z-x\right)\left(y-z\right)}\left(a^{z+x-y}\right)^{z-x}\)
- step9: Transform the expression:
\(a^{\left(x+y-z\right)\left(x-y\right)}\times a^{\left(y+z-x\right)\left(y-z\right)}\times a^{\left(z+x-y\right)\left(z-x\right)}\)
- step10: Multiply the terms:
\(a^{\left(x+y-z\right)\left(x-y\right)+\left(y+z-x\right)\left(y-z\right)+\left(z+x-y\right)\left(z-x\right)}\)
- step11: Add the terms:
\(a^{0}\)
- step12: Evaluate the power:
\(1\)
Let's solve the problems step by step.
### a. Finding the HCF (Highest Common Factor)
The expression given is:
\[
x^{2}+2xy+y^{2}-z^{2}xy^{2}+2y z+z^{2}-x^{2}(3)
\]
However, it seems that the expression is not in a standard form for finding the HCF. The HCF is typically calculated for a set of numbers or polynomials. Since the expression is complex and does not represent a clear set of terms, I cannot directly compute the HCF from it.
If you have specific terms or polynomials you want to find the HCF for, please provide them.
### b. Simplifying the Expression
The expression to simplify is:
\[
\left(\frac{a^{x+y}}{a^{z}}\right)^{x-y}\left(\frac{a^{y+z}}{a^{x}}\right)^{y-z}\left(\frac{a^{z+x}}{a^{y}}\right)^{z-x}
\]
The result of this simplification is:
\[
1
\]
This means that the entire expression simplifies to 1.
If you have any further questions or need additional assistance, feel free to ask!
Answered by UpStudy AI and reviewed by a Professional Tutor
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Beyond the Answer
पहिलो भागको म.स. निकाल्नको लागि, हामी समिकरणलाई पुनर्व्यवस्थित गरौं र सामान्य कारकहरूको समूह बनाएर आंतरक्रियालाई ध्यानमा राख्नुपर्छ। त्यसपछि, हरिऔंको थालनीमा \(xy^2\) र शेष तत्वहरूको पुनरावलोकन गर्दा, सामान्य तत्त्वहरू जस्तै \(x\), \(y\), र \(z\) को जोडले म.स. भन्न सकिन्छ। दोस्रो भागलाई सरल बनाउनको लागि, प्रत्येक अंशको आधारलाई समेटेर एकै ठाउँमा ल्याइँदा, हामी गणितीय गुणनको विशेषता प्रयोग गर्न सक्छौं। यद्यपि, अंशहरूलाई पुन: व्यवस्थित गरिसकेपछि, आधारको समानता र घटावको नियम प्रयोग गरेर हामीले विश्वसनीय उत्तर सजिलै प्राप्त गर्न सक्छौं।