B. \( 25-x=21+(24+x) \) C. \( (24-x)+(21-x)=25 \) D. \( (24-x)+25=x \) Use this surustion to complete the circle pettern. \( x=\square \) \( y=\square \) \( z=\square \)

Let's solve each equation step by step to find the values of \( x \), \( y \), and \( z \). ### Equation B: \[ 25 - x = 21 + (24 + x) \] 1. Simplify the right side: \[ 25 - x = 21 + 24 + x \] \[ 25 - x = 45 + x \] 2. Rearranging gives: \[ 25 - 45 = x + x \] \[ -20 = 2x \] 3. Solving for \( x \): \[ x = -10 \] ### Equation C: \[ (24 - x) + (21 - x) = 25 \] 1. Substitute \( x = -10 \): \[ (24 - (-10)) + (21 - (-10)) = 25 \] \[ (24 + 10) + (21 + 10) = 25 \] \[ 34 + 31 = 25 \] This is incorrect, so we need to solve it without substitution. 2. Combine like terms: \[ 24 - x + 21 - x = 25 \] \[ 45 - 2x = 25 \] 3. Rearranging gives: \[ 45 - 25 = 2x \] \[ 20 = 2x \] 4. Solving for \( x \): \[ x = 10 \] ### Equation D: \[ (24 - x) + 25 = x \] 1. Substitute \( x = 10 \): \[ (24 - 10) + 25 = 10 \] \[ 14 + 25 = 10 \] This is incorrect, so we need to solve it without substitution. 2. Rearranging gives: \[ 24 - x + 25 = x \] \[ 49 - x = x \] 3. Rearranging gives: \[ 49 = 2x \] 4. Solving for \( x \): \[ x = 24.5 \] Now we have the values for \( x \), \( y \), and \( z \). Let's summarize: - From Equation B, we found \( x = -10 \). - From Equation C, we found \( y = 10 \). - From Equation D, we found \( z = 24.5 \). Thus, we can fill in the squares: \[ x = -10 \] \[ y = 10 \] \[ z = 24.5 \]