Question 9 Solve for: \( x^{2}+8 x-20=3 x-6 \) Important: Be sure to submit in order from least to greatest! \( x= \) Blank 1 \( x= \) Blank 2

To solve the equation \( x^{2}+8 x-20=3 x-6 \), start by moving all terms to one side to set the equation to zero: \[ x^2 + 8x - 20 - 3x + 6 = 0 \] This simplifies to: \[ x^2 + 5x - 14 = 0 \] Next, you can use the quadratic formula \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \( a = 1, b = 5, c = -14 \): Calculate the discriminant: \[ b^2 - 4ac = 5^2 - 4 \cdot 1 \cdot -14 = 25 + 56 = 81 \] Now apply the quadratic formula: \[ x = \frac{-5 \pm \sqrt{81}}{2 \cdot 1} = \frac{-5 \pm 9}{2} \] This gives us two solutions: 1. \( x = \frac{4}{2} = 2 \) 2. \( x = \frac{-14}{2} = -7 \) Arranging these from least to greatest, we have: \( x= -7 \) \( x= 2 \) So your answers are: \( x= \) Blank 1: -7 \( x= \) Blank 2: 2