The number of banks in a country for the years 1935 through 2009 is given by the following function. \( f(x)=\left\{\begin{array}{r}84.8 x+12,365 \text { if } x<90 \\ -376.3 x+48,686 \text { if } x \geq 90\end{array}\right. \), where \( x \) is the number of years after 1900 Complete parts (a)-(b). a) What does this model give as the number of banks in \( 1970 ? 1990 ? 2020 \) ? The number of banks in 1970 is
Upstudy AI Solution
Answer
Solution

Sign in to Unlock Answers for Free!
A Learning Platform Trusted by Millions of Real Students and Teachers.

Answered by UpStudy AI and reviewed by a Professional Tutor
Bonus Knowledge
To find the number of banks in the years 1970, 1990, and 2020 using the given function, we first determine the corresponding values of \( x \). - For 1970: \( x = 70 \) (1970 - 1900) - For 1990: \( x = 90 \) (1990 - 1900) - For 2020: \( x = 120 \) (2020 - 1900) Now we can calculate: 1. **For 1970** (\( x = 70 \)): Since \( x < 90 \): \[ f(70) = 84.8(70) + 12,365 \] \[ = 5,936 + 12,365 \] \[ = 18,301 \] So, the number of banks in 1970 is **18,301**. 2. **For 1990** (\( x = 90 \)): Since \( x \geq 90 \): \[ f(90) = -376.3(90) + 48,686 \] \[ = -33,867 + 48,686 \] \[ = 14,819 \] So, the number of banks in 1990 is **14,819**. 3. **For 2020** (\( x = 120 \)): Since \( x \geq 90 \): \[ f(120) = -376.3(120) + 48,686 \] \[ = -45,156 + 48,686 \] \[ = 3,530 \] So, the number of banks in 2020 is **3,530**. In summary: - The number of banks in 1970 is **18,301**. - The number of banks in 1990 is **14,819**. - The number of banks in 2020 is **3,530**.