Wro te Output CLS FOR $$ A=1 $$ TO 5 READ N\$ A\$=MID\$ $$ (N \$, A, 1) $$ B\$=B\$+A\$ NEXT A DATA NEHA, NEETA, GOPAL, MONA, RAHUL PRINT B\$ END

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- The program declares a loop that will iterate from $$ A = 1 $$ to $$ 5 $$.
- Inside the loop, it uses the statement  
  $$
  \texttt{READ } N\$
  $$
  to read successive data items from the DATA statement.
- The DATA statement is:  
  $$
  \texttt{DATA NEHA, NEETA, GOPAL, MONA, RAHUL}
  $$
- In each iteration, the program extracts a character from the string $$ N\$ $$ using the command  
  $$
  A\$ = \texttt{MID\$}(N\$, A, 1)
  $$
  which picks the $$ A^\text{th} $$ character from $$ N\$ $$.
- The extracted character $$ A\$ $$ is concatenated to the string $$ B\$ $$ by  
  $$
  B\$ = B\$ + A\$
  $$
- Detailed breakdown of each iteration:
  - **Iteration 1 ($$ A = 1 $$)**:
    - $$ N\$ = \texttt{NEHA} $$
    - The 1st character is $$\texttt{N}$$.
    - $$ B\$ $$ becomes $$\texttt{N}$$.
  - **Iteration 2 ($$ A = 2 $$)**:
    - $$ N\$ = \texttt{NEETA} $$
    - The 2nd character is $$\texttt{E}$$.
    - $$ B\$ $$ updates to $$\texttt{NE}$$.
  - **Iteration 3 ($$ A = 3 $$)**:
    - $$ N\$ = \texttt{GOPAL} $$
    - The 3rd character is $$\texttt{P}$$.
    - $$ B\$ $$ becomes $$\texttt{NEP}$$.
  - **Iteration 4 ($$ A = 4 $$)**:
    - $$ N\$ = \texttt{MONA} $$
    - The 4th character is $$\texttt{A}$$.
    - $$ B\$ $$ becomes $$\texttt{NEPA}$$.
  - **Iteration 5 ($$ A = 5 $$)**:
    - $$ N\$ = \texttt{RAHUL} $$
    - The 5th character is $$\texttt{L}$$.
    - $$ B\$ $$ becomes $$\texttt{NEPAL}$$.
- Finally, the statement  
  $$
  \texttt{PRINT } B\$
  $$
  outputs the string $$ B\$ $$.
- Therefore, the output of the program is:

$$
\boxed{\texttt{NEPAL}}
$$
The program reads the first five characters from each name in the DATA statement and concatenates them to form "NEPAL". So, the output is NEPAL.

Wro te Output CLS FOR \( A=1 \) TO 5 READ N\$ A\$=MID\$ \( (N \$, A, 1) \) B\$=B\$+A\$ NEXT A DATA NEHA, NEETA, GOPAL, MONA, RAHUL PRINT B\$ END

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