7-8. Imagine a standard deck of cards with all of the aces and twos removed. Find each probability below. Homework Help (Deck of cards is 52 cards. 4 aces and 4 twos) a. P (heart) b. P (black) c. P (face card) d. How is the P (face card) different with this deck from the probability if the deck was not missing any cards? Which probability is greater? Why?
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In a standard deck of cards, removing all the aces and twos leaves 52 - 8 = 44 cards. Since there are 11 hearts (removing 2 hearts) out of these 44 cards, the probability of drawing a heart is P(heart) = 11/44 or 1/4. Now, considering the colors, black cards consist of spades and clubs. In a full deck, there’d be 26 black cards; removing 4 cards leaves us with 22 black cards. So, P(black) = 22/44 or 1/2. The original deck has 12 face cards (3 per suit). With the removal of Aces and Twos, we're left with 12 face cards as no face card was removed initially. So, P(face card) = 12/44. Before the removal, P(face card) = 12/52, which simplifies to 3/13. Comparing the two probabilities, the probability for face cards is lower in the reduced deck because there are simply fewer total cards. The overall ratio of face cards to total cards has increased, meaning the original deck held a higher probability of drawing any face card.