A certain forest covers an area of \( 3100 \mathrm{~km}^{2} \). Suppose that each year this area decreases by \( 9 \% \). What will the area be after 10 years? Use the calculator provided and round your answer to the nearest square kilometer.

To determine the area of the forest after 10 years, you can use the formula for exponential decay: \[ A = A_0(1 - r)^t \] where: - \( A_0 \) is the initial area (\( 3100 \, \text{km}^2 \)), - \( r \) is the rate of decrease (9% or 0.09), - \( t \) is the number of years (10). Plugging in the values: \[ A = 3100(1 - 0.09)^{10} \] \[ A = 3100(0.91)^{10} \] \[ A = 3100(0.42241) \quad \text{(approximately)} \] \[ A \approx 1305.47 \, \text{km}^2 \] Rounding to the nearest square kilometer, the area after 10 years will be approximately \( 1305 \, \text{km}^2 \). So, the area of the forest after 10 years will be about 1305 km².