Solve using substitution. \[ \begin{array}{l}y=-6 x+7 \\ y=-2 x-1\end{array} \] \( (\square, \square) \)

To solve the system using substitution, you can start with the first equation \( y = -6x + 7 \) and substitute this expression for \( y \) in the second equation. Replacing \( y \) in the second equation, you get: \[ -6x + 7 = -2x - 1. \] Now, solve for \( x \) by first moving all terms involving \( x \) to one side: \[ -6x + 2x = -1 - 7. \] This simplifies to: \[ -4x = -8, \] leading to: \[ x = 2. \] Substituting \( x = 2 \) back into the first equation gives: \[ y = -6(2) + 7 = -12 + 7 = -5. \] So the solution to the system is \( (2, -5) \). Now we can box the answer: \( (2, -5) \)