Identify the perimeter of a rectangle in which $$ h=8 \mathrm{ft} $$ and $$ A=144 x \mathrm{ft}^{2} $$. $$ P=(8 x+16) \mathrm{ft} $$ $$ P=(8+16 x) \mathrm{ft} $$ $$ P=(16+36 x) \mathrm{ft} $$ $$ P=(16 x+36) \mathrm{ft} $$

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We are given the following information for a rectangle:
- Height: $$ h = 8 \, \text{ft} $$
- Area: $$ A = 144x \, \text{ft}^2 $$

**Step 1. Compute the Length:**  
The area of a rectangle is given by  
$$
A = \text{length} \times \text{height}
$$
Substitute the given values:
$$
144x = \text{length} \times 8
$$
Solve for the length:
$$
\text{length} = \frac{144x}{8} = 18x
$$

**Step 2. Compute the Perimeter:**  
The perimeter $$P$$ of a rectangle is given by  
$$
P = 2 \times (\text{length} + \text{height})
$$
Substitute the computed length and the given height:
$$
P = 2 \times (18x + 8) = 36x + 16
$$
Thus, the perimeter is  
$$
P = (16 + 36x) \, \text{ft}
$$

The correct answer is:

$$ P=(16+36 x) \, \text{ft} $$
The perimeter of the rectangle is $$ P = (16 + 36x) \, \text{ft} $$.

Identify the perimeter of a rectangle in which and
.

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