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\begin{tabular}{l} TRY IT Identify the Critical Re \\ A company advertises that there are an average of \\ 25 grams of potato chips in each bag of chips. A \\ consumer group has collected a sample and \\ wants to perform a test to see if the company is \\ providing less than it advertises. \\ \( H_{0}: \mu=25 \) \\ Which type of significance test should be used for \\ this situation? \\ \hline\end{tabular}

Ask by Guerrero Reid. in the United States
Feb 25,2025

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Answer

A one-tailed t-test should be used for this situation.

Solution

This situation calls for a one‐sample significance test for the mean. Specifically, because the alternative hypothesis is that the actual mean is less than the advertised 25 grams, you would perform a one‐tailed (left‐tailed) test. If the population standard deviation is unknown (which is often the case), you would use a one‐sample t‐test; if it were known and the sample size sufficiently large, you could use a one‐sample z‐test.

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The Deep Dive

To tackle the situation, a one-sample t-test would be the most appropriate choice. This test is ideal when you're looking to compare the sample mean of the potato chips to the known population mean (25 grams) while also considering the variability within your sample. It helps determine if the mean weight is significantly less than the advertised amount. Keep in mind that it's essential to check the assumptions for a t-test before diving in, such as whether the sample is drawn from a normally distributed population or if the sample size is sufficiently large (typically n > 30). If these conditions are met, you're all set to proceed with your hypothesis test!

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