Perform the indicated operations. Write the answer in standard form, \( a+b i \). \[ (2-6 i)^{2}+(2+6 i)^{2}=\square \]

To perform the operations, let's first calculate \( (2-6i)^{2} \) and \( (2+6i)^{2} \). 1. Calculating \( (2-6i)^{2} \): \[ (2-6i)^{2} = 2^{2} - 2 \cdot 2 \cdot 6i + (6i)^{2} = 4 - 24i - 36 = -32 - 24i \] 2. Calculating \( (2+6i)^{2} \): \[ (2+6i)^{2} = 2^{2} + 2 \cdot 2 \cdot 6i + (6i)^{2} = 4 + 24i - 36 = -32 + 24i \] Now we add the two results: \[ (2-6i)^{2} + (2+6i)^{2} = (-32 - 24i) + (-32 + 24i) \] Combining like terms, we get: \[ -32 - 32 + (-24i + 24i) = -64 + 0i = -64 \] Thus, the final answer in standard form \( a + bi \) is: \[ \boxed{-64} \]