Question

21. \( 5 \sqrt{2 x} \cdot 3 \sqrt{7 x^{2} y^{3}} \)

Ask by Hodges Ball. in the United States
Feb 25,2025

Upstudy AI Solution

Tutor-Verified Answer

Answer

The simplified form is \( 15xy\sqrt{14xy} \).

Solution

To simplify the expression 5√(2x) · 3√(7x²y³): 1. Multiply the coefficients:   5 × 3 = 15 2. Combine the square roots:   √(2x) · √(7x²y³) = √((2x)·(7x²y³)) = √(14x³y³) 3. Factor inside the square root to extract perfect squares:   x³ = x² · x  and  y³ = y² · y   Thus, √(14x³y³) = √(14 · x² · y² · x · y) = √(14x²y²) · √(xy)   Since √(x²) = x and √(y²) = y (assuming x, y ≥ 0), we have:   √(14x²y²) = xy√14 4. Now, combine all factors:   15 · (xy√(14xy)) = 15xy√(14xy) Thus, the simplified form is:   15xy√(14xy)

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The Deep Dive

To simplify \( 5 \sqrt{2 x} \cdot 3 \sqrt{7 x^{2} y^{3}} \), we start by multiplying the coefficients and then the square roots. First, we can multiply the coefficients: \[ 5 \cdot 3 = 15 \] Next, we simplify the square roots: \[ \sqrt{2x} \cdot \sqrt{7x^{2}y^{3}} = \sqrt{(2x)(7x^{2}y^{3})} = \sqrt{14x^{3}y^{3}} \] Now we combine everything: \[ 15 \sqrt{14x^{3}y^{3}} \] We can further simplify the square root: \[ \sqrt{14x^{3}y^{3}} = \sqrt{14} \cdot \sqrt{x^{3}} \cdot \sqrt{y^{3}} = \sqrt{14} \cdot x^{1.5} \cdot y^{1.5} = \sqrt{14} \cdot x \sqrt{x} \cdot y \sqrt{y} \] Thus, the final expression is: \[ 15 \sqrt{14} x \sqrt{x} y \sqrt{y} \] Overall, the simplified expression is: \[ 15 \sqrt{14} xy \sqrt{xy} \]

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