Brittany is going to ascend a six-step staircase. At any time, she is just as likely to stride up one step or three steps. Find the probability of the event that she will ascend the six steps in the following number of strides. \( \begin{array}{ll}\text { a. two strides } & \text { b. four strides } \\ \text { c. six strides }\end{array} \) \( \begin{array}{l}\text { a. The probability that Brittany will ascend the staircase in two strides is } \frac{1}{4}\end{array} \) (Type an integer or a simplified fraction.) \( \begin{array}{l}\text { b. The probability that Brittany will ascend the staircase in four strides is } \\ \text { (Type an integer or a simplified fraction.) }\end{array} \)
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To find the probabilities of Brittany ascending the six-step staircase in two and four strides, we first analyze the combinations of strides that can achieve a total of six steps. a. **Two Strides:** If Brittany takes two strides to ascend six steps, the only option is to take two strides of three steps each. There is exactly one way to do this: (3, 3). Given each stride has a probability of \(\frac{1}{2}\) (1 step or 3 steps), the probability of this event is: \[ P(2 \text{ strides}) = (1/2) \times (1/2) = \frac{1}{4}. \] b. **Four Strides:** For four strides to equal six steps, we can have a combination of one-step and three-step strides. The possible combinations of strides to make six steps in four strides are: 1. Three 1-step strides and one 3-step stride. The combinations for this are: - \( (1, 1, 1, 3) \) with one 3-step stride. Since we have 4 positions to arrange one 3-step stride among three 1-step strides, we can calculate it as follows: \[ \text{Ways} = \frac{4!}{3! \cdot 1!} = 4. \] Each of these strategies occurs with a probability of: \[ P(1, 1, 1, 3) = (1/2)^4 = \frac{1}{16}. \] Thus, the probability of ascending the staircase in four strides is: \[ P(4 \text{ strides}) = 4 \cdot \frac{1}{16} = \frac{1}{4}. \] Therefore, Brittany will ascend the staircase: - The probability that Brittany will ascend the staircase in **two strides** is \(\frac{1}{4}\). - The probability that Brittany will ascend the staircase in **four strides** is also \(\frac{1}{4}\).