Tell whether each addition problem has a sum greater than \( \frac{1}{2} \). \( \begin{array}{ll}\text { a. } \frac{4}{10}+\frac{9}{100} & \square \text { Yes } \\ \text { b. } \frac{1}{100}+\frac{5}{10} & \square \text { No } \\ \text { e. } \frac{45}{100}+\frac{1}{10} & \square \text { Yes } \\ \text { I. } \frac{25}{100}+\frac{3}{10} & \square \text { No } \\ \frac{3}{10}+\frac{15}{100} & \square \text { Yes } \\ \text { Yes } & \square \text { No }\end{array} \)

**Problem a.** We have \[ \frac{4}{10}+\frac{9}{100}=\frac{40}{100}+\frac{9}{100}=\frac{49}{100}. \] Since \[ \frac{49}{100}<\frac{50}{100}=\frac{1}{2}, \] the sum is not greater than \(\frac{1}{2}\). **Problem b.** We have \[ \frac{1}{100}+\frac{5}{10}=\frac{1}{100}+\frac{50}{100}=\frac{51}{100}. \] Since \[ \frac{51}{100}>\frac{50}{100}=\frac{1}{2}, \] the sum is greater than \(\frac{1}{2}\). **Problem e.** We have \[ \frac{45}{100}+\frac{1}{10}=\frac{45}{100}+\frac{10}{100}=\frac{55}{100}. \] Since \[ \frac{55}{100}>\frac{50}{100}=\frac{1}{2}, \] the sum is greater than \(\frac{1}{2}\). **Problem I.** We have \[ \frac{25}{100}+\frac{3}{10}=\frac{25}{100}+\frac{30}{100}=\frac{55}{100}. \] Since \[ \frac{55}{100}>\frac{50}{100}=\frac{1}{2}, \] the sum is greater than \(\frac{1}{2}\). **Next Problem (\(\frac{3}{10}+\frac{15}{100}\)).** We have \[ \frac{3}{10}+\frac{15}{100}=\frac{30}{100}+\frac{15}{100}=\frac{45}{100}. \] Since \[ \frac{45}{100}<\frac{50}{100}=\frac{1}{2}, \] the sum is not greater than \(\frac{1}{2}\). **Summary of Answers** - \( \frac{4}{10}+\frac{9}{100} \): No - \( \frac{1}{100}+\frac{5}{10} \): Yes - \( \frac{45}{100}+\frac{1}{10} \): Yes - \( \frac{25}{100}+\frac{3}{10} \): Yes - \( \frac{3}{10}+\frac{15}{100} \): No