Solve using substitution \[ \begin{array}{l}y=3 x+6 \\ y=2 x+1\end{array} \] \( (, \square) \)

To solve the system of equations using substitution, we start with the two equations given: 1. \( y = 3x + 6 \) 2. \( y = 2x + 1 \) Since both equations equal \( y \), we can set them equal to each other: \[ 3x + 6 = 2x + 1 \] Now, let's solve for \( x \). Subtract \( 2x \) from both sides: \[ 3x - 2x + 6 = 1 \] This simplifies to: \[ x + 6 = 1 \] Next, subtract 6 from both sides: \[ x = 1 - 6 \] \[ x = -5 \] Now we can substitute \( x = -5 \) back into one of the original equations to find \( y \). Using the second equation: \[ y = 2(-5) + 1 \] \[ y = -10 + 1 \] \[ y = -9 \] Thus, the solution to the system of equations is: \((-5, -9)\)