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Solve the inequality. Write the solution set in interval notation if possible. Simplify your answer, if necessar \( -3 u^{4}+27 u^{3}-45 u^{2}-75 u \geq 0 \) The solution set is \( \square . \square \square \square \square \square \square][\square, \square] \)

Ask by Craig Gordon. in the United States
Mar 19,2025

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Tutor-Verified Answer

Answer

The solution set is \( u \in [-1, 0] \cup \{5\} \).

Solution

Solve the equation \( -3u^{4}+27u^{3}-45u^{2}-75u \geq 0 \). Solve the inequality by following steps: - step0: Solve the inequality by testing the values in the interval: \(-3u^{4}+27u^{3}-45u^{2}-75u\geq 0\) - step1: Rewrite the expression: \(-3u^{4}+27u^{3}-45u^{2}-75u=0\) - step2: Factor the expression: \(-3u\left(u-5\right)^{2}\left(u+1\right)=0\) - step3: Divide both sides: \(u\left(u-5\right)^{2}\left(u+1\right)=0\) - step4: Separate into possible cases: \(\begin{align}&u=0\\&\left(u-5\right)^{2}=0\\&u+1=0\end{align}\) - step5: Solve the equation: \(\begin{align}&u=0\\&u=5\\&u=-1\end{align}\) - step6: Determine the test intervals: \(\begin{align}&u<-1\\&-15\end{align}\) - step7: Choose a value: \(\begin{align}&u_{1}=-2\\&u_{2}=-\frac{1}{2}\\&u_{3}=3\\&u_{4}=6\end{align}\) - step8: Test the chosen value: \(\begin{align}&u<-1\textrm{ }\textrm{is not a solution}\\&-15\textrm{ }\textrm{is not a solution}\end{align}\) - step9: Include the critical value: \(\begin{align}&-1\leq u\leq 0\textrm{ }\textrm{is the solution}\\&u=5\end{align}\) - step10: The final solution is \(u \in \left[-1,0\right]\cup \left\{5\right\}:\) \(u \in \left[-1,0\right]\cup \left\{5\right\}\) The solution set for the inequality \( -3u^{4}+27u^{3}-45u^{2}-75u \geq 0 \) is \( u \in [-1,0] \cup \{5\} \).

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Bonus Knowledge

To solve the inequality \( -3u^{4}+27u^{3}-45u^{2}-75u \geq 0 \), we first factor it out. The expression can be factored as \( -3u(u^3 - 9u^2 + 15u + 25) \geq 0 \). Let’s find critical points by setting the equation to zero: Setting \( -3u = 0 \) gives \( u = 0 \). For the cubic polynomial \( u^3 - 9u^2 + 15u + 25 = 0 \), we can use numerical methods or graphing techniques to find its roots. Once we identify the roots, we will evaluate the intervals between these critical values to determine where the expression is positive. After solving the complete cubic, we might find the intervals such as \( (-\infty, -5] \), \( [0, 5] \) for our inequality. Thus, the solution set is \( (-\infty, -5] \cup [0, 5] \).

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