2) Kia and Lee will play a game, To decide who will go first, Lee rolls a 6 sided die and gets 4. What is the probability that Kia will roll a higher number, namely 5 or 6? \( 1 / 6 \) \( 1 / 6+1 / 6=2 / 6 \) \( 5 / 6 \) \( 51 / 3+1 / 3=2 / 3 \)

To determine the probability that Kia rolls a higher number than Lee's roll of 4 on a 6-sided die, let's analyze the possible outcomes: 1. **Possible Outcomes for Kia:** - Since Lee rolled a 4, Kia needs to roll either a **5** or a **6** to have a higher number. 2. **Counting the Favorable Outcomes:** - There are **2** favorable outcomes for Kia (5 and 6). 3. **Total Possible Outcomes:** - A standard 6-sided die has **6** possible outcomes (1, 2, 3, 4, 5, 6). 4. **Calculating the Probability:** \[ \text{Probability} = \frac{\text{Number of Favorable Outcomes}}{\text{Total Possible Outcomes}} = \frac{2}{6} = \frac{1}{3} \] **Conclusion:** The probability that Kia will roll a higher number (5 or 6) is **\(\frac{1}{3}\)**. Among the provided options, the closest matching answer is: \[ \frac{1}{6} + \frac{1}{6} = \frac{2}{6} = \frac{1}{3} \] **Correct Answer:** \( \frac{1}{6} + \frac{1}{6} = \frac{2}{6} \)