26. \( \int \frac{d x}{\operatorname{sen}^{2} x \cdot \cos ^{2} x} \)
Upstudy AI Solution
Answer
Solution
Answered by UpStudy AI and reviewed by a Professional Tutor


Mind Expander
To solve the integral \( \int \frac{d x}{\sin^{2} x \cdot \cos^{2} x} \), we can use a trigonometric identity. Recall that \( \sin^{2} x = 1 - \cos^{2} x \) and \( \cos^{2} x = 1 - \sin^{2} x \). However, for this integral, a more straightforward approach is to rewrite it in terms of \( \tan x \) or \( \cot x \): We express \( \sin^{2} x \cdot \cos^{2} x \) as \( \frac{\sin^{2} x}{\cos^{2} x} \cdot \frac{\cos^{4} x}{\cos^{2} x} = \tan^{2} x \cdot \cos^{4} x \). Thus, we can rewrite our integral as: \[ \int \frac{1}{\sin^{2} x \cdot \cos^{2} x} \, dx = \int \frac{1}{\cos^{2} x} \cdot \frac{1}{\sin^{2} x} \, dx = \int \sec^{2} x \csc^{2} x \, dx \] Using the substitution \( u = \tan x \), we have \( du = \sec^{2} x \, dx \), and we substitute: The integral now becomes: \[ \int \frac{1}{u^{2}} \, du \] This results in the integral: \[ - \frac{1}{u} + C = -\cot x + C \] So, the final answer is: \[ \int \frac{d x}{\sin^{2} x \cdot \cos^{2} x} = -\cot x + C \]