Question

26. \( \int \frac{d x}{\operatorname{sen}^{2} x \cdot \cos ^{2} x} \)

Ask by Schmidt Malone. in Dominican Republic
Mar 01,2025

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Tutor-Verified Answer

Answer

La integral es \( -2\cot(2x) + C \).

Solution

Calculate the integral \( \int \frac{1}{\sin^2(x) \cos^2(x)} dx \). Evaluate the integral by following steps: - step0: Evaluate using formulas and rules: \(\int \frac{1}{\sin^{2}\left(x\right)\cos^{2}\left(x\right)} dx\) - step1: Multiply the terms: \(\int \frac{1}{\left(\sin\left(x\right)\cos\left(x\right)\right)^{2}} dx\) - step2: Rewrite the expression: \(\int 4\sin^{-2}\left(2x\right) dx\) - step3: Rewrite the expression: \(\int \frac{4}{\sin^{2}\left(2x\right)} dx\) - step4: Rewrite the expression: \(\int 4\times \frac{1}{\sin^{2}\left(2x\right)} dx\) - step5: Use properties of integrals: \(4\times \int \frac{1}{\sin^{2}\left(2x\right)} dx\) - step6: Evaluate the integral: \(4\left(-\frac{1}{2}\right)\cot\left(2x\right)\) - step7: Calculate: \(4\left(-\frac{1}{2}\cot\left(2x\right)\right)\) - step8: Rewrite the expression: \(-4\times \frac{1}{2}\cot\left(2x\right)\) - step9: Multiply the terms: \(-2\cot\left(2x\right)\) - step10: Add the constant of integral C: \(-2\cot\left(2x\right) + C, C \in \mathbb{R}\) La integral de \( \frac{1}{\sin^2(x) \cos^2(x)} \) con respecto a \( x \) es \( -2\cot(2x) + C \), donde \( C \) es una constante real.

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To solve the integral \( \int \frac{d x}{\sin^{2} x \cdot \cos^{2} x} \), we can use a trigonometric identity. Recall that \( \sin^{2} x = 1 - \cos^{2} x \) and \( \cos^{2} x = 1 - \sin^{2} x \). However, for this integral, a more straightforward approach is to rewrite it in terms of \( \tan x \) or \( \cot x \): We express \( \sin^{2} x \cdot \cos^{2} x \) as \( \frac{\sin^{2} x}{\cos^{2} x} \cdot \frac{\cos^{4} x}{\cos^{2} x} = \tan^{2} x \cdot \cos^{4} x \). Thus, we can rewrite our integral as: \[ \int \frac{1}{\sin^{2} x \cdot \cos^{2} x} \, dx = \int \frac{1}{\cos^{2} x} \cdot \frac{1}{\sin^{2} x} \, dx = \int \sec^{2} x \csc^{2} x \, dx \] Using the substitution \( u = \tan x \), we have \( du = \sec^{2} x \, dx \), and we substitute: The integral now becomes: \[ \int \frac{1}{u^{2}} \, du \] This results in the integral: \[ - \frac{1}{u} + C = -\cot x + C \] So, the final answer is: \[ \int \frac{d x}{\sin^{2} x \cdot \cos^{2} x} = -\cot x + C \]

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