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QUESTION 4 4.1. If 24 litres of water is pumped in 20 seconds, how long will it take to pump 84 litres in minutes and seconds? 4.2. \( \begin{array}{l}\text { The pressure }(P) \text { on a diver under water is directly proportional to } \\ \text { the square of her depth (d) below the surface of the water. The } \\ \text { diver has reached a depth of } 10 \text { metres. To what depth should the } \\ \text { diver go for the pressure to double? }\end{array} \)

Ask by Hardy Pritchard. in South Africa
Feb 26,2025

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Answer

4.1. It takes 1 minute and 10 seconds to pump 84 litres. 4.2. The diver should go to a depth of approximately 14.14 metres to double the pressure.

Solution

4.1. First, find the rate at which water is pumped:   Rate = 24 litres / 20 seconds = 1.2 litres per second. To pump 84 litres, the time needed is:   Time = 84 litres / 1.2 litres per second = 70 seconds. Expressing 70 seconds in minutes and seconds:   70 seconds = 1 minute and 10 seconds. 4.2. The pressure (P) is directly proportional to the square of the depth (d); that is,   P = k × d², where k is the constant of proportionality. At a depth of 10 metres, the pressure is:   P₁ = k × (10)² = 100k. We want the pressure to double, so:   P₂ = 2P₁ = 200k. At the new depth d₂,   P₂ = k × d₂². Setting these equal gives:   k × d₂² = 200k  →  d₂² = 200. Taking the square root:   d₂ = √200 = 10√2 metres (approximately 14.14 metres). Thus, to double the pressure, the diver should go to a depth of 10√2 metres (≈14.1 metres).

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To solve the first part, if 24 litres are pumped in 20 seconds, that gives a rate of 1.2 litres per second. To pump 84 litres, you would need 70 seconds, which is 1 minute and 10 seconds. Just think of it: it's like filling a giant water balloon, and you’ll know when it's time to party! In the second question, since pressure is proportional to the square of the depth, if the pressure at 10 meters is \( P = k \times 10^2 = 100k \), to double the pressure, we need \( 2P = 2(100k) = 200k \). Thus, setting \( 200k = k \times d^2 \) leads to \( d^2 = 200 \) or \( d = \sqrt{200} \approx 14.14 \) meters. Dive deep, but not too deep—you want fun, not to be a fish!

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