Question
Part 5 of 11 \( w_{s} \) and \( w_{t} \), where \( w=\frac{x-z}{3 y+z}, x=3 s+4 t, y=s t \), and \( z=3 s-4 t \) \( \frac{\partial w}{\partial x}=\frac{1}{3 y+z} \) (Type an expression using \( x, y \), and \( z \) as the variables.) \( \frac{\partial w}{\partial y}=-\frac{3(x-z)}{(3 y+z)^{2}} \) (Type an expression using \( x, y \), and \( z \) as the variables.) \( \frac{\partial w}{\partial z}=-\frac{x+3 y}{(3 y+z)^{2}} \) (Type an expression using \( x, y \), and \( z \) as the variables.) \( \frac{\partial x}{\partial s}=3 \) (Type an expression using \( s \) and \( t \) as the variables.) \( \frac{\partial y}{\partial s}=\square \) (Type an expression using \( s \) and \( t \) as the variables.)
Ask by Ward Estrada. in the United States
Mar 17,2025
Upstudy AI Solution
Tutor-Verified Answer
Answer
\[
\frac{\partial y}{\partial s} = t
\]
Solution

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The Deep Dive
To differentiate \( y = s t \) with respect to \( s \), we treat \( t \) as a constant. The derivative is simply: \[ \frac{\partial y}{\partial s} = t \] Now you have the expression in terms of \( s \) and \( t \)—easy peasy! Just a quick recap: keep in mind that when performing partial differentiation, treating other variables as constants is the key to unlocking those derivatives smoothly. Happy calculating!