Question
\( 120=2 \times 2 \times 2 \times 3 \quad \) LCM \( =24 \) Sipho and Busi share 8 sweets in the ratio \( 3: 5 \). Show by calculations he many sweets will each get.
Ask by Macdonald Kirk. in South Africa
Mar 13,2025
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Answer
Sipho gets 3 sweets and Busi gets 5 sweets.
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To find how many sweets Sipho and Busi will get, we’ll first add the parts of the ratio \(3 + 5 = 8\). This means they are splitting 8 sweets into 8 parts. Now, Sipho will receive \( \frac{3}{8} \) of the total sweets, which equals \( \frac{3}{8} \times 8 = 3 \) sweets. Busi will receive \( \frac{5}{8} \) of the total sweets, equal to \( \frac{5}{8} \times 8 = 5 \) sweets. Therefore, Sipho gets 3 sweets, and Busi gets 5 sweets.