$$ 120=2 imes 2 imes 2 imes 3 \quad $$ LCM $$ =24 $$ Sipho and Busi share 8 sweets in the ratio $$ 3: 5 $$. Show by calculations he many sweets will each get.

Question

$$ 120=2 	imes 2 	imes 2 	imes 3 \quad $$ LCM $$ =24 $$ Sipho and Busi share 8 sweets in the ratio $$ 3: 5 $$. Show by calculations he many sweets will each get.

UpStudy AI · Accepted Answer

To solve the problem of how many sweets Sipho and Busi will get, we can follow these steps:

1. **Understand the ratio**: Sipho and Busi share the sweets in the ratio $$3:5$$. This means that for every 3 parts Sipho gets, Busi gets 5 parts.

2. **Calculate the total parts**: 
   - The total parts in the ratio is $$3 + 5 = 8$$ parts.

3. **Determine the value of each part**: 
   - Since there are 8 sweets to be shared, we can find the value of one part by dividing the total number of sweets by the total parts:
   $$
   \text{Value of one part} = \frac{8 \text{ sweets}}{8 \text{ parts}} = 1 \text{ sweet per part}
   $$

4. **Calculate the number of sweets for each person**:
   - For Sipho:
   $$
   \text{Sweets for Sipho} = 3 \text{ parts} \times 1 \text{ sweet per part} = 3 \text{ sweets}
   $$
   - For Busi:
   $$
   \text{Sweets for Busi} = 5 \text{ parts} \times 1 \text{ sweet per part} = 5 \text{ sweets}
   $$

5. **Conclusion**: 
   - Sipho will get $$3$$ sweets, and Busi will get $$5$$ sweets.

Thus, the final answer is:
- Sipho: $$3$$ sweets
- Busi: $$5$$ sweets
Sipho gets 3 sweets and Busi gets 5 sweets.

\( 120=2 \times 2 \times 2 \times 3 \quad \) LCM \( =24 \) Sipho and Busi share 8 sweets in the ratio \( 3: 5 \). Show by calculations he many sweets will each get.

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