\( 120=2 \times 2 \times 2 \times 3 \quad \) LCM \( =24 \) Sipho and Busi share 8 sweets in the ratio \( 3: 5 \). Show by calculations he many sweets will each get.

To solve the problem of how many sweets Sipho and Busi will get, we can follow these steps: 1. **Understand the ratio**: Sipho and Busi share the sweets in the ratio \(3:5\). This means that for every 3 parts Sipho gets, Busi gets 5 parts. 2. **Calculate the total parts**: - The total parts in the ratio is \(3 + 5 = 8\) parts. 3. **Determine the value of each part**: - Since there are 8 sweets to be shared, we can find the value of one part by dividing the total number of sweets by the total parts: \[ \text{Value of one part} = \frac{8 \text{ sweets}}{8 \text{ parts}} = 1 \text{ sweet per part} \] 4. **Calculate the number of sweets for each person**: - For Sipho: \[ \text{Sweets for Sipho} = 3 \text{ parts} \times 1 \text{ sweet per part} = 3 \text{ sweets} \] - For Busi: \[ \text{Sweets for Busi} = 5 \text{ parts} \times 1 \text{ sweet per part} = 5 \text{ sweets} \] 5. **Conclusion**: - Sipho will get \(3\) sweets, and Busi will get \(5\) sweets. Thus, the final answer is: - Sipho: \(3\) sweets - Busi: \(5\) sweets