43 How many g are required to have 0.100 mol of each of the following? $$ \begin{array}{ll} ext { a. } \mathrm{CH}_{4} ext { (methane) } & ext { c. } \mathrm{NaOH}\end{array} $$

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43 How many g are required to have 0.100 mol of each of the following? $$ \begin{array}{ll}	ext { a. } \mathrm{CH}_{4} 	ext { (methane) } & 	ext { c. } \mathrm{NaOH}\end{array} $$

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**a. CH$$_4$$ (methane):**

1. Calculate the molar mass of CH$$_4$$:
   $$
   \text{Molar mass of CH}_{4} = M_{\text{C}} + 4 \times M_{\text{H}} = 12.01\,\text{g/mol} + 4(1.008\,\text{g/mol}) \approx 16.04\,\text{g/mol}
   $$
2. Multiply the number of moles by the molar mass:
   $$
   0.100\,\text{mol} \times 16.04\,\text{g/mol} = 1.604\,\text{g}
   $$

**c. NaOH:**

1. Calculate the molar mass of NaOH:
   $$
   \text{Molar mass of NaOH} = M_{\text{Na}} + M_{\text{O}} + M_{\text{H}} = 22.99\,\text{g/mol} + 16.00\,\text{g/mol} + 1.008\,\text{g/mol} \approx 40.00\,\text{g/mol}
   $$
2. Multiply the number of moles by the molar mass:
   $$
   0.100\,\text{mol} \times 40.00\,\text{g/mol} = 4.00\,\text{g}
   $$

Thus, you require approximately $$1.604\,\text{g}$$ of CH$$_4$$ and $$4.00\,\text{g}$$ of NaOH.
You need 1.604 grams of methane (CH₄) and 4.00 grams of sodium hydroxide (NaOH).

43 How many g are required to have 0.100 mol of each of the
following?

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