Campbell Boyd
05/31/2023 · Middle School

10. An object is thrown upward at a speed of \( 189 \) feet per second by a machine from a height of \( 13 \) feet off the ground. The height of the object after \( t \) seconds can be found using the equation \( s ( t ) = - 16 t ^ { 2 } + v _ { 0 } t + s _ { 0 } \) , where \( v _ { 0 } \) is the initial velocity and \( s _ { 0 } \) is the initial height. Give all numerical answers to \( 2 \) decimal places.  a) When will the object reach its maximum height? b) What is its maximum height? 

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\(v_ 0= 189\\ s_ 0= 13\)

 

\(s( t) = - 16t^ 2+ 189t+ 13\)

 

 

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