A survey of 2304 adults in a certain large country aged 18 and older conducted by a reputable polling organization found that 409 have donated blood in the past two years. Complete parts (a) through (c) below. (c) Construct and interpret a \( 90 \% \) confidence interval for the population proportion of adults in the country who have donated blood in the past two years. Select the correct choice below and fill in any answer boxes within your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) A. There is a \( \square \% \) chance the proportion of adults in the country aged 18 and older who have donated blood in the past two years is between \( \square \) and \( \square \). We are \( \square \% \) confident the proportion of adults in the country aged 18 and older who have donated blood in the past two years is between \( \square \) and \( \square \).

Что такое диаграмма рассеяния и для чего она используется?

A person's blood glucose level and diabetes are dosely related. Let \( x \) be a random variable measured in milligrams of glucose per deciliter ( \( 1 / 10 \) of a liter) of blood. Suppose that after a 12 -hoi fast, the random variable \( x \) will have a distribution that is approximately normal with mean \( \mu=87 \) and standard deviation \( \sigma=23 \). Note: After 50 years of age, both the mean and standard deviation tend to increase. For an adult (under 50 ) after a 12-hour fast, find the following probabilities. (Round your answers to four decimal places.) (a) \( x \) is more than 60 (b) \( x \) is less than 110 (c) \( x \) is between 60 and 110 (d) \( x \) is greater than 125 (borderline diabetes starts at 125 )

Find the median. \( \begin{array}{l}0.88,1.18,0.64,1.62,0.75,0.85 \\ 1.18,1.53,0.91,0.88,1.39,1.07 \\ 0.47,1.39,0.85,1.07,1.72,0.75 \\ 1.12,0.89,0.56\end{array} \)

The test scores of 40 students are listed below. Find \( \mathrm{P}_{85} \). \( \begin{array}{l}30,35,43,44,47,48,54,55,56,57,59,62,63,65,66,68,69,69,71,72,72,73, \\ 74,76,77,77,78,79,80,81,81,82,83,85,89,92,93,94,97,98\end{array} \)

How many college students are needed to estimate the mean grade point average of all current college students in the United Sates within 20\% percentage points with a \( 99 \% \) confidence. An earlier study gave an estimate of 0.79 for the population standard deviation. \( \mathrm{n}= \)