Gegeben sind drei unabhängige Ereignisse mit den Wahrscheinlichkeiten \( P(A)=0,4 ; P(B)=0,8 \) und \( P(C)=0,3 \). Berechnen Sie die Wahrscheinlichkeit für das Ereignis \( D: C \) und \( B \) treten ein, aber nicht \( A \) Geben Sie den Wert als Prozentzahl auf zwei Nachkommastellen gerundet ein und lassen Sie das \%-Zeichen weg.

Between 12:00 PM and 1:00 PM, cars arrive at a local bank's drive-thru at the rate of 8 cars per hour ( 0.13 car per minute). The formula below from probability can be used to determine the probability that a car will arrive within t minutes of 12:00 PM. Use this information to answer the questions given below in parts (a)-(e). F(t) \( =1-e^{-0.13 t} \) (a) What is the probability that a car will arrive within 35 minutes of \( 12: 00 \) PM (that is, before 12:35 PM)? \( \mathrm{F}(35)=0.989 \) (Round to three decimal places as needed.) (b) What is the probability that a car will arrive within 40 minutes of \( 12: 00 \) PM (that is, before 12:40 PM)? F(40) \( =\square \) (Round to three decimal places as needed.)

Between 12:00 PM and 1:00 PM, cars arrive at a local bank's drive-thru at the rate of 8 cars per hour ( 0.13 car per minute). The formula below from probability can be used to determine the probability that a car will arrive within \( t \) minutes of 12:00 PM. Use this information to answer the questions given below in parts (a)-(e). \( F(t)=1-e^{-0.13 t} \) (a) What is the probability that a car will arrive within 35 minutes of 12:00 PM (that is, before 12:35 PM)? (Round to three decimal places as needed.)

Pass Completions Football player Peyton Manning completes a pass \( 64.8 \% \) of the time. Find the probability that (a) the first pass Peyton completes is the second pass, (b) the first pass Peyton completes is the first or second pass, and (c) Peyton does not complete his first two passes. (Source: National Football League)

Between 12:00 PM and 1:00 PM, cars arrive at a bank's drive-thru at the rate of 18 cars per hour ( 0.3 car per minute). The following formula from statistics can be used to determine the probability that a car will arrive within t minutes of 12:00 PM. Complete parts (a)-(c). F(t) \( =1-e^{-0.3 t} \) (a) Determine how many minutes are needed for the probability to reach 30\%. About 1.19 minutes are needed for the probability to reach \( 30 \% \). (Round to two decimal places as needed.) (b) Determine how many minutes are needed for the probability to reach \( 90 \% \). About 7.68 minutes are needed for the probability to reach \( 90 \% \). (Round to two decimal places as needed.) (c) Is it possible for the probability to equal \( 100 \% \) ? Explain. Select the correct choice below and, if necessary, fill in the answer box within your choice. A. Yes, about \( \square \) minutes are needed for the probability to B. No, because when determining the number of minutes, the (Round to two decimal places as needed.)

Between 12:00 PM and 1:00 PM, cars arrive at a bank's drive-thru at the rate of 18 cars per hour ( 0.3 car per minute). The following formula from statistics can be used to determine the probability that a car will arrive within \( t \) minutes of 12:00 PM. Complete parts (a)-(c). F(t) \( =1-e^{-0.3 t} \) (a) Determine how many minutes are needed for the probability to reach 30\%. About \( \square \) minutes are needed for the probability to reach 30\%. (Round to two decimal places as needed.)