Pierce Burgess
06/12/2023 · Elementary School
A person invest in an account with interest compounded continuously according to the formula \( A=f(t)=8200 e^{0.059 t} \) where \( A \) is the amount in the account and \( t \) is in years. Find \( f(0)=\$ \) To the nearest cent, find the amount in the account after 8 years. \( \$ \) To the nearest tenth of a year, determine how long it will take for the investment to grow to \( \$ 10100 \).
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\( f(0) = \$8200 \)
After 8 years, the amount is \( \$13125.60 \)
It will take approximately \( 3.6 \) years to grow to \( \$10100 \).
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