$$ 1.1 .4 \quad 2^{r \sqrt{x}}=2^{27} $$ $$ 1.1 .5 \quad x^{2}

Question

$$ 1.1 .4 \quad 2^{r \sqrt{x}}=2^{27} $$ $$ 1.1 .5 \quad x^{2}<-2 x+15 $$ Solve for $$ x $$ and $$ y $$ simultaneously if: $$ 3-y+2 x=0 $$ and $$ 6 x+4 y^{2}=3+5 x y $$ Given that $$ 9 x^{2}-12 p x=-4 p^{2} $$ : Determine the value(s) of $$ p $$ for which the equation will have equal roots.

Barnett Stanley · Accepted Answer

1. $$ x = \frac{729}{r^2} $$ 2. $$ -5 < x < 3 $$ 3. Solutions for $$ (x, y) $$: $$ (-1, 1) $$ and $$ (-5.5, -8) $$ 4. The equation has equal roots for all values of $$ p $$.

\( 1.1 .4 \quad 2^{r \sqrt{x}}=2^{27} \) \( 1.1 .5 \quad x^{2}<-2 x+15 \) Solve for \( x \) and \( y \) simultaneously if: \( 3-y+2 x=0 \) and \( 6 x+4 y^{2}=3+5 x y \) Given that \( 9 x^{2}-12 p x=-4 p^{2} \) : Determine the value(s) of \( p \) for which the equation will have equal roots.

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\( 1.1 .4 \quad 2^{r \sqrt{x}}=2^{27} \) \( 1.1 .5 \quad x^{2}<-2 x+15 \) Solve for \( x \) and \( y \) simultaneously if: \( 3-y+2 x=0 \) and \( 6 x+4 y^{2}=3+5 x y \) Given that \( 9 x^{2}-12 p x=-4 p^{2} \) : Determine the value(s) of \( p \) for which the equation will have equal roots.

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