The solution set in $$ \mathbb{Q} $$ for the equation $$ 4(x-8)=2 x+1 $$ is $$ \begin{array}{ll} ext { (a) }\{17\} & ext { (b) } \varnothing \ ext { (c) }\left\{16 \frac{1}{2} ight\} & ext { (d) }\{20\}\end{array} $$

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The solution set in $$ \mathbb{Q} $$ for the equation $$ 4(x-8)=2 x+1 $$ is $$ \begin{array}{ll}	ext { (a) }\{17\} & 	ext { (b) } \varnothing \ 	ext { (c) }\left\{16 \frac{1}{2}ight\} & 	ext { (d) }\{20\}\end{array} $$

Frank Christensen · Accepted Answer

الإجابة هي $$ x = 16.5 $$ أو $$ x = \frac{33}{2} $$، مما يعني أن مجموعة الحلول هي $$ \left\{16 \frac{1}{2}\right\} $$، أي خيار (c).

The solution set in \( \mathbb{Q} \) for the equation \( 4(x-8)=2 x+1 \) is \( \begin{array}{ll}\text { (a) }\{17\} & \text { (b) } \varnothing \\ \text { (c) }\left\{16 \frac{1}{2}\right\} & \text { (d) }\{20\}\end{array} \)

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The solution set in \( \mathbb{Q} \) for the equation \( 4(x-8)=2 x+1 \) is \( \begin{array}{ll}\text { (a) }\{17\} & \text { (b) } \varnothing \\ \text { (c) }\left\{16 \frac{1}{2}\right\} & \text { (d) }\{20\}\end{array} \)

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