Scores on the GRE (Graduate Record Examination) are normally distributed with a mean of 577 and a standard deviation of 104. Use the 68 -95-99.7 Rule to find the percentage of people taking the test who score between 473 and 681 . The percentage of people taking the test who score between 473 and 681 is \( \square \% \).

Find the range of the following data set. Assume the data set is a sample.

\( n-1=35-1=34 \) \( p \)-value \( <0.01 \) - Step 6: Make a decision to reject or not reject the null hypothesis. Write in non-techni terms a final conclusion about the claim. 'd reject the nurl nypo thesis

Assume that \( z \)-scores are normally distributed with a mean of 0 and a standard deviation of 1 . If \( P(-b<z<b)=0.7944 \), find \( b \). \( b=\square \) Submit Question

You wish to test the following claim \( \left(H_{a}\right) \) at a significance level of \( \alpha=0.05 \) \[ \begin{array}{l}H_{o}: \mu=72.3 \\ H_{a}: \mu \neq 72.3\end{array} \] You believe the population is normally distributed, but you do not know the standard deviation. You obta a sample of size \( n=5 \) with mean \( M=78.2 \) and a standard deviation of \( S D=18.8 \). What is the p-value for this sample? (Report answer accurate to four decimal places.) -value \( =\square \)

pose that grade point averages of undergraduate students at one university have a bell-shaped distribution with a mean of 2.6 and a standard deviation of 0.42 cribe where approximately \( 95 \% \) of grade point averages lie. swer \[ \text { below } 1.76 \text { and above } 3.44 \] between 1.76 and 3.18 and above 3.02