The position vector of boat \( \mathrm{A}, \mathrm{t} \) hours after leaving the port O is \( \mathrm{t}\binom{30}{15} \) while the position vector of boat B is \( \binom{50}{5}+\mathrm{t}\binom{10}{10} \). Determine the velocity of boat A and boat B . Will the two boats meet?

In \( \triangle \mathrm{EFG}, e=880 \) inches, \( f=140 \) inches and \( g=890 \) inches. Find the measure of \( \angle \mathrm{G} \) to the nearest 10th of a degree.

In \( \triangle \mathrm{EFG}, e=96 \mathrm{~cm}, f=71 \mathrm{~cm} \) and \( \angle \mathrm{G}=52^{\circ} \). Find the length of \( g \), to the nearest centimeter.

In \( \triangle \mathrm{NOP}, n=54 \) inches, \( o=97 \) inches and \( p=95 \) inches. Find the measure of \( \angle \mathrm{N} \) to the nearest degree.

\( \left. \begin{array} { l } { \frac { ( 1 - h ) ^ { 2 } } { a ^ { 2 } } + \frac { ( y - k ) ^ { 2 } } { b ^ { 2 } } = 1 } \\ { \frac { h ^ { 2 } } { a ^ { 2 } } + \frac { [ ( 3 - \frac { \pi } { 2 } ) - k ] ^ { 2 } } { b ^ { 2 } } = 1 } \\ { \frac { ( - 1 - h ) ^ { 2 } } { a ^ { 2 } } + \frac { ( 1 - k ) ^ { 2 } } { b ^ { 2 } } = 1 } \\ { \frac { ( - 5 - h ) ^ { 2 } } { a ^ { 2 } } + \frac { ( 3 - k ) ^ { 2 } } { b ^ { 2 } } = 1 } \end{array} \right. \)

In \( \triangle \mathrm{TUV}, u=750 \mathrm{~cm}, v=670 \mathrm{~cm} \) and \( \angle \mathrm{T}=160^{\circ} \). Find the length of \( t \), to the nearest centimeter.