Joseph Page
11/15/2024 · Primary School

Um elevador percorre uma distância de 190 m e atinge uma velocidade máxima de \( \mathrm{m} / \mathrm{min} \). 0 elevador acelera a partir do repouso e desacelera de volta ao repouso a uma de \( 1,22 \mathrm{~m} / \mathrm{s} 2 \). (a) Qual é a distância percorrida pelo elevador enquanto acelera a parti repouso até a velocidade máxima? (b)Quanto tempo o elevador leva para percorr distância de 190 m , sem paradas, partindo do repouso e chegando com velocidade zero

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(a) A distância percorrida pelo elevador enquanto acelera até a velocidade máxima é de 95 m. (b) O elevador leva aproximadamente 24.94 segundos para percorrer a distância de 190 m.

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