Find \( (f \circ g)(x) \) and \( (g \circ f)(x) \) and the domain of each. \( f(x)=x+3, g(x)=2 x^{2}-5 x-3 \) \( (f \circ g)(x)=\square( \) Simplify your answer.) The domain of \( (f \circ g)(x) \) is \( \square \). (Type your answer in interval notation.) \( (g \circ f)(x)=\square( \) Simplify your answer.) The domain of \( (g \circ f)(x) \) is \( \square \). (Type your answer in interval notation.)

Evaluate the following function. Your answer should be an integer. \( f(x)=-3^{2 x-2} \), for \( x=3 \) Your answer is \( f(3)=\square \)

\( \log _ { 2 } ^ { 2 } x - 15 \log _ { 5 } x - 4 \leq 0 \)

268. Решите уравнение: \( \begin{array}{l}\text { a) }(y+2)\left(y^{2}-2 y+4\right)-y(y-3)(y+3)=44 \text {; } \\ \text { б) }(m-3)\left(m^{2}+3 m+9\right)-m(m+2)(m-2)=13 \\ \text { (B) }(3 a+1)\left(9 a^{2}-3 a+1\right)-3 a\left(9 a^{2}+4\right)=25 \text {; } \\ \text { (A) }(2 n-1)\left(4 n^{2}+2 n+1\right)-4 n\left(2 n^{2}-5\right)=21 \text {. }\end{array} \)

Вычислить следующие определители: а) \( \left|\begin{array}{cc}1 & -2 \\ -2 & 4\end{array}\right| \); б) \( \left|\begin{array}{ccc}1 & 2 & 0 \\ 0 & 0 & 3 \\ 5 & 0 & -1\end{array}\right| \), 2. Найти точку пересечения прямых \( l_{1}: 3 x-2 y=0 \) и \( l_{2}: y=-x+5 \). Построить прямые.

268. Решите уравнение: \( \begin{array}{l}\text { а) }(y+2)\left(y^{2}-2 y+4\right)-y(y-3)(y+3)=44 \text {; } \\ \text { б) }(m-3)\left(m^{2}+3 m+9\right)-m(m+2)(m-2)=13 \text {; } \\ \text { B) }(3 a+1)\left(9 a^{2}-3 a+1\right)-3 a\left(9 a^{2}+4\right)=25 \text {; }(2 n-1)\left(4 n^{2}+2 n+1\right)-4 n\left(2 n^{2}-5\right)=21 \text {. }\end{array} \).