Coleman Paul
08/04/2024 · Senior High School
Para el modo dominante del ascilador de Gunn, la frecuencia de resonancia vicne dada por \[ f_{i e o}=\frac{c}{2} \sqrt{\frac{1}{s^{2}}+\frac{1}{b^{2}}}=9.46 G H z \] donde \( b=23 \) min es la anchura de la cavidad y \( s=22 \) min es la distancia entre el diafragma perforado y el elemento Gunn.
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La frecuencia de resonancia del oscilador de Gunn es aproximadamente \( 9.46 \, \text{GHz} \).
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